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m^2=-2m-1
We move all terms to the left:
m^2-(-2m-1)=0
We get rid of parentheses
m^2+2m+1=0
a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{-2}{2}=-1$
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